![]() ![]() Print(timeit. Print(timeit.timeit("sample_bits(1024)", setup="from _main_ import sample_bits", number=10000)) Rbytes = np.random.randint(0, 255, dtype=np.uint8, size=n_bytes) Here is some more demo-approach using numpy (which surprisingly does not have a method dedicated for this job exactly): import numpy as np If you need many bits or can pre-calculate bit-arrays for later consumption, numpy's methods might shine. ![]() If you need single bits (one per call), you already did your benchmark and other answers provide additional info. Although method 1 is shortest (main advantege) for now I would choose method 3: def positive_or_negative():Īny better (faster or shorter) method to randomly generate -1 or 1 in Python? Any reason why would you choose method 1 over method 3 or vice versa? Also both method 1 (since Python 3.6 I think?) and 3 give the possibility to introduce uneven distributions. ![]() My bet was on method 1 to be the fastest as it is also shortest. If the absolute value of the negative integer is the largest, then the sum is negative. You can verify the size of your integers by printing a sizeof (int) Share. If the integers have different signs, then subtract the absolute values of the integers. Remember how we used subtraction to represent distances on a number line When absolute value comes to the rescue, that works with integers, too. If we do the math with 16 bit signed integers and overflow: 255 195 -15810 Overflow math: (-32768 + (49725 - 32767)) -15810 / 200 -79. Let's extend our addition and subtraction understanding to include negative numbers. Timeit.timeit(stmt = s, setup = "import random") My guess is that your device is running with 16 bit integers. # if I understand correctly random.random() should never return exactly 1 We could write it as (+6) + (3) (+3) The last two examples showed us that taking away balloons (subtracting a positive) or adding weights (adding a negative) both make the basket go down. In the real number system, a negative number is a number that is less than zero.Negative numbers are often used to represent the magnitude of a loss or deficiency. In mathematics, a negative number represents an opposite. What would be the best way to generate 1 or -1 in Python? Assuming even distribution I know I could use: import random 'Positive 6 plus Negative 3 equals Positive 3'. This thermometer is indicating a negative Fahrenheit temperature (4 ☏). As you get better at this, just using the rule should help you get to the answer.I wanted to generate 1 or -1 in Python as a step to randomizing between non-negative and non-positive numbers or to randomly changing sign of an already existing integer. To find the product of two integers, we multiply their absolute values and give the result a plus sign if both the numbers have the same sign or a minus sign. As you begin adding integers with different signs, you may want to use one of the first three methods. There are a few different ways you can visualize adding positive and. So the answer is -7.Īs you can see, no matter which method you choose, the opposites will cancel out, and you will get to the answer. The same thing is true if you add a positive 1 to a negative 1, they cancel each other out. This can also be thought of as 18 - 11 = 7, but the larger absolute value (18) has a negative sign. However, 23 is larger than 13, so we take the sign of the 23, which happens to be negative. ![]() You can download some free number line worksheets to help students understand the concept of the number line. Both of those numbers will fall on either side of the number line, but they may not adhere to the same rules. Numbers higher than zero are positive numbers. Subtract the absolute values of the numbers and the use the sign of the larger absolute value. Numbers lower than zero are called negative numbers. Rule for adding integers with different signs: Once you get good at adding integers, you can also just think of the rule. In each method, the opposites are adding to a total of zero to give us the answer. We will start at -11 and then add positive 4. ![]()
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